Table of Content
2K2[OsO2(OH)4] | → | 2KOH | + | Os(OH)4 | + | K2[OsO4(OH)2] | |
Potassium osmate(VI) | potassium hydroxide | Osmium tetrahydroxide | Potassium perosmate | ||||
(dung dịch pha loãng) | (kt) | ||||||
2 | 2 | 1 | 1 | Hệ số | |||
Nguyên - Phân tử khối (g/mol) | |||||||
Số mol | |||||||
Khối lượng (g) |
Temperature: boiled
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
In a full sentence, you can also say K2[OsO2(OH)4] (Potassium osmate(VI)) and produce KOH (potassium hydroxide) and Os(OH)4 (Osmium tetrahydroxide) and K2[OsO4(OH)2] (Potassium perosmate)
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance K2[OsO4(OH)2] (Potassium perosmate), appearing at the end of the reaction.
Or if any of the following reactant substances K2[OsO2(OH)4] (Potassium osmate(VI)), disappearing
We no further information about this chemical reactions.
Potassium osmate(VI)
2K2[OsO2(OH)4] → 2KOH + Os(OH)4 + K2[OsO4(OH)2] 2K2[OsO2(OH)4] → 2H2O + 4KOH + OsO2 + OsO4 3H2 + K2[OsO2(OH)4] → 4H2O + 2KOH + Os View all equations with K2[OsO2(OH)4] as reactant
Potassium osmate(VI)
KClO3 + Os + 2KOH.H2O → H2O + KCl + K2[OsO2(OH)4] 3O2 + 2Os + 4KOH.H2O → 2H2O + 2K2[OsO2(OH)4] H2O + KNO2 + 2KOH + OsO4 → KNO3 + K2[OsO2(OH)4] View all equations with K2[OsO2(OH)4] as product
Potassium osmate(VI)
3O2 + 2Os + 4KOH.H2O → 2H2O + 2K2[OsO2(OH)4] KClO3 + Os + 2KOH.H2O → H2O + KCl + K2[OsO2(OH)4] H2O + KNO2 + 2KOH + OsO4 → KNO3 + K2[OsO2(OH)4] View all equations with K2[OsO2(OH)4] as product
Potassium osmate(VI)
3O2 + 2Os + 4KOH.H2O → 2H2O + 2K2[OsO2(OH)4] KClO3 + Os + 2KOH.H2O → H2O + KCl + K2[OsO2(OH)4] H2O + KNO2 + 2KOH + OsO4 → KNO3 + K2[OsO2(OH)4] View all equations with K2[OsO2(OH)4] as product
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