Table of Content
HClO4 | + | NH2OH | → | (NH3OH)ClO4 | |
perchloric acid | Hydroxylamine; Hydroxyamine | ||||
(dung dịch pha loãng) | |||||
1 | 1 | 1 | Hệ số | ||
Nguyên - Phân tử khối (g/mol) | |||||
Số mol | |||||
Khối lượng (g) |
No information found for this chemical equation
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
In a full sentence, you can also say HClO4 (perchloric acid) reacts with NH2OH (Hydroxylamine; Hydroxyamine) and produce (NH3OH)ClO4 ()
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance (NH3OH)ClO4, appearing at the end of the reaction.
Or if any of the following reactant substances NH2OH (Hydroxylamine; Hydroxyamine), disappearing
We no further information about this chemical reactions.
perchloric acid
2HClO4 → H2O + Cl2O7 2F2 + 4HClO4 → 2H2O + O2 + 4ClO3F PH3 + HClO4 → PH4ClO4 View all equations with HClO4 as reactantHydroxylamine; Hydroxyamine
2H + NH2OH → NH4OH HClO4 + NH2OH → (NH3OH)ClO4 H2SO4 + 2NH2OH → (NH3OH)2SO4 View all equations with NH2OH as reactantHydroxylamine; Hydroxyamine
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