Table of Content
C2H5ONa | + | (NH3OH)Cl | → | C2H5OH | + | NaCl | + | NH2OH | |
(c2h5)2nh diethylamine | sodium chloride | Hydroxylamine; Hydroxyamine | |||||||
(kt) | |||||||||
1 | 1 | 1 | 1 | 1 | Hệ số | ||||
Nguyên - Phân tử khối (g/mol) | |||||||||
Số mol | |||||||||
Khối lượng (g) |
Catalyst: Ethanol
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
In a full sentence, you can also say C2H5ONa () reacts with (NH3OH)Cl () and produce C2H5OH ((c2h5)2nh diethylamine) and NaCl (sodium chloride) and NH2OH (Hydroxylamine; Hydroxyamine)
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance NH2OH (Hydroxylamine; Hydroxyamine), appearing at the end of the reaction.
Or if any of the following reactant substances (NH3OH)Cl, disappearing
We no further information about this chemical reactions.
CH3COOH + C2H5ONa → NaOH + CH3COOC2H5 H2O + CO2 + C2H5ONa → C2H5OH + NaHCO3 HCl + C2H5ONa → C2H5OH + NaCl View all equations with C2H5ONa as reactant
4(NH3OH)Cl → 3H2O + 2HCl + 2NH4Cl + N2O C2H5ONa + (NH3OH)Cl → C2H5OH + NaCl + NH2OH 2HI + (NH3OH)Cl → H2O + I2 + NH4Cl View all equations with (NH3OH)Cl as reactant
3H2 + 2HCl + 2NO → 2(NH3OH)Cl HCl + NH2OH → (NH3OH)Cl HCl + NO2 + 5H → H2O + (NH3OH)Cl View all equations with (NH3OH)Cl as product
3H2 + 2HCl + 2NO → 2(NH3OH)Cl HCl + NH2OH → (NH3OH)Cl HCl + NO2 + 5H → H2O + (NH3OH)Cl View all equations with (NH3OH)Cl as product
3H2 + 2HCl + 2NO → 2(NH3OH)Cl HCl + NO2 + 5H → H2O + (NH3OH)Cl HCl + NH2OH → (NH3OH)Cl View all equations with (NH3OH)Cl as product
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