Table of Content
|potassium hydroxide||sulfur||water||potassium sulfide|
|(không màu)||(vàng)||(không màu)||(không màu)||(không màu)|
|Nguyên - Phân tử khối (g/mol)|
|Khối lượng (g)|
No information found for this chemical equation
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
In a full sentence, you can also say KOH (potassium hydroxide) reacts with S (sulfur) and produce H2O (water) and K2S (potassium sulfide) and K2SO3 ()
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance K2SO3, appearing at the end of the reaction.
Or if any of the following reactant substances S (sulfur), disappearing
We no further information about this chemical reactions.
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potassium hydroxide2KOH + Mg(NO3)2 → 2KNO3 + Mg(OH)2 KOH + FeCl3 → KCl + Fe(OH)3 2KOH + CH3NH3HCO3 → H2O + K2CO3 + CH3NH2 View all equations with KOH as reactant
sulfurFe + S → FeS H2 + S → H2S 3C + 2KNO3 + S → K2S + N2 + 3CO2 View all equations with S as reactant
sulfurCl2 + H2S → 2HCl + S 2H2S + 2NO → 2H2O + N2 + 2S Ag2S → 2Ag + S View all equations with S as product
sulfurCl2 + H2S → 2HCl + S 2C + SO2 → 2CO + S 2H2S + 2NO → 2H2O + N2 + 2S View all equations with S as product
sulfurCl2 + H2S → 2HCl + S 2H2 + SO2 → 2H2O + S 2H2S + O2 → 2H2O + 2S View all equations with S as product
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