Table of Content
|potassium hydroxide||copper(ii) sulfate||copper(ii) hydroxide||potassium sulfate|
|(không màu)||(xanh lam)||(xanh)||(không màu)|
|Nguyên - Phân tử khối (g/mol)|
|Khối lượng (g)|
No information found for this chemical equation
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
In a full sentence, you can also say KOH (potassium hydroxide) reacts with CuSO4 (copper(ii) sulfate) and produce Cu(OH)2 (copper(ii) hydroxide) and K2SO4 (potassium sulfate)
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance K2SO4 (potassium sulfate), appearing at the end of the reaction.
Or if any of the following reactant substances CuSO4 (copper(ii) sulfate), disappearing
We no further information about this chemical reactions.
potassium hydroxide2KOH + Mg(NO3)2 → 2KNO3 + Mg(OH)2 KOH + FeCl3 → KCl + Fe(OH)3 2KOH + CH3NH3HCO3 → H2O + K2CO3 + CH3NH2 View all equations with KOH as reactant
copper(ii) sulfate2H2O + 2K + CuSO4 → Cu(OH)2 + H2 + K2SO4 Fe + CuSO4 → Cu + FeSO4 Zn + CuSO4 → Cu + ZnSO4 View all equations with CuSO4 as reactant
copper(ii) sulfateCu + 2H2SO4 → 2H2O + SO2 + CuSO4 3Cu + 4H2SO4 + 2NaNO3 → 4H2O + Na2SO4 + 2NO + 3CuSO4 6H2SO4 + Cu2S → 6H2O + 5SO2 + 2CuSO4 View all equations with CuSO4 as product
copper(ii) sulfateCu + 2H2SO4 → 2H2O + SO2 + CuSO4 3Cu + 4H2SO4 + 2NaNO3 → 4H2O + Na2SO4 + 2NO + 3CuSO4 H2SO4 + CuCO3 → H2O + CO2 + CuSO4 View all equations with CuSO4 as product