Table of Content
|sulfuric acid||potassium hydroxide||water||potassium sulfate|
|(không màu)||(không màu)||(không màu)||(trắng)|
|Nguyên - Phân tử khối (g/mol)|
|Khối lượng (g)|
No information found for this chemical equation
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
H2SO4 reacts with KOH
In a full sentence, you can also say H2SO4 (sulfuric acid) reacts with KOH (potassium hydroxide) and produce H2O (water) and K2SO4 (potassium sulfate)
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance K2SO4 (potassium sulfate), appearing at the end of the reaction.
Or if any of the following reactant substances KOH (potassium hydroxide), disappearing
We no further information about this chemical reactions.
sulfuric acid10FeO + 18H2SO4 + 2KMnO4 → 5Fe2(SO4)3 + 18H2O + 2MnSO4 + K2SO4 H2SO4 + Na2SO3 → H2O + Na2SO4 + SO2 H2SO4 + Zn → H2 + ZnSO4 View all equations with H2SO4 as reactant
potassium hydroxide2KOH + Mg(NO3)2 → 2KNO3 + Mg(OH)2 KOH + FeCl3 → KCl + Fe(OH)3 2KOH + CH3NH3HCO3 → H2O + K2CO3 + CH3NH2 View all equations with KOH as reactant
potassium hydroxide2NaOH + K2HPO4 → 2KOH + Na2HPO4 H2O + K2O → 2KOH 3C2H4 + 4H2O + 2KMnO4 → 2KOH + 2MnO2 + 3C2H4(OH)2 View all equations with KOH as product