Table of Content
|hydrogen sulfide||potassium hydroxide||water||Potassium hydrogensulfide; Potassium hydrosulfide|
|Nguyên - Phân tử khối (g/mol)|
|Khối lượng (g)|
No information found for this chemical equation
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
In a full sentence, you can also say H2S (hydrogen sulfide) reacts with KOH (potassium hydroxide) and produce H2O (water) and KSH (Potassium hydrogensulfide; Potassium hydrosulfide)
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance KSH (Potassium hydrogensulfide; Potassium hydrosulfide), appearing at the end of the reaction.
Or if any of the following reactant substances KOH (potassium hydroxide), disappearing
We no further information about this chemical reactions.
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hydrogen sulfide2H2S + 3O2 → 2H2O + 2SO2 Cl2 + H2S → 2HCl + S 2H2S + 2NO → 2H2O + N2 + 2S View all equations with H2S as reactant
potassium hydroxide2KOH + Mg(NO3)2 → 2KNO3 + Mg(OH)2 KOH + FeCl3 → KCl + Fe(OH)3 KOH + HCOOCH3 → CH3OH + HCOOK View all equations with KOH as reactant
potassium hydroxide2NaOH + K2HPO4 → 2KOH + Na2HPO4 3C2H4 + 4H2O + 2KMnO4 → 2KOH + 2MnO2 + 3C2H4(OH)2 H2O + K2O → 2KOH View all equations with KOH as product
potassium hydroxideH2O + K2O → 2KOH 2NaOH + K2HPO4 → 2KOH + Na2HPO4 3C2H4 + 4H2O + 2KMnO4 → 2KOH + 2MnO2 + 3C2H4(OH)2 View all equations with KOH as product
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