Table of Content
|hydrogen sulfide||potassium hydroxide||water||potassium sulfide|
|Nguyên - Phân tử khối (g/mol)|
|Khối lượng (g)|
No information found for this chemical equation
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
In a full sentence, you can also say H2S (hydrogen sulfide) reacts with KOH (potassium hydroxide) and produce H2O (water) and K2S (potassium sulfide)
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance Rb2S (potassium sulfide), appearing at the end of the reaction.
Or if any of the following reactant substances RbOH (potassium hydroxide), disappearing
We no further information about this chemical reactions.
hydrogen sulfide2H2S + 3O2 → 2H2O + 2SO2 Cl2 + H2S → 2HCl + S 4Cl2 + 4H2O + H2S → H2SO4 + 8HCl View all equations with H2S as reactant
potassium hydroxide2KOH + Mg(NO3)2 → 2KNO3 + Mg(OH)2 KOH + FeCl3 → KCl + Fe(OH)3 2KOH + CH3NH3HCO3 → H2O + K2CO3 + CH3NH2 View all equations with KOH as reactant
potassium hydroxideH2O + K2O → 2KOH 2NaOH + K2HPO4 → 2KOH + Na2HPO4 3C2H4 + 4H2O + 2KMnO4 → 2KOH + 2MnO2 + 3C2H4(OH)2 View all equations with KOH as product