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2H2O + O2 + 4K2MnO4 → 4KMnO4 + 4KOH | Phương Trình Phản Ứng Hóa Học
H2O | water | solid + O2 | oxygen | solid + K2MnO4 | | solid = KMnO4 | potassium permanganate | solid + KOH | potassium hydroxide | solid | Temperature: temperature, Other Condition excess chlorine
Introduce
Detailed information about the equation
Reaction conditions when applied H2O + O2 + K2MnO4
- Catalyst: not available
- Temperature: normal
- Pressure: normal
- Other conditions: not available
Reaction process H2O + O2 + K2MnO4
Process: Let K2MO4 be oxidized in the presence of water vapor to produce a purple solution
Note: not available
The result of the reaction H2O + O2 + K2MnO4
The phenomenon: Purple solution appears
Detailed information on the reactants
Information about H2O (water)
Information about O2 (oxygen)
Information about K2MnO4
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Detailed information about the products of the reaction
Information about KMnO4 (potassium permanganate)
- Atomic weight: 158.0339
- Color: hình cái kim màu tím-xám màu đỏ tươi trong dung dịch
- Status: chất rắn
Information about KOH (potassium hydroxide)
Total rating:
Rating: / 5 star
The equations for preparation H2O
Catalyst
normal
Temperature
> 70
Pressure
normal
Other conditions
normal
Catalyst
normal
Temperature
normal
Pressure
normal
Other conditions
normal
→ 4 + +
Catalyst
normal
Temperature
168 - 185
Pressure
normal
Other conditions
normal
The equations for preparation O2
Catalyst
normal
Temperature
normal
Pressure
normal
Other conditions
normal
Catalyst
normal
Temperature
160 - 300
Pressure
normal
Other conditions
normal
Catalyst
normal
Temperature
temperature
Pressure
normal
Other conditions
normal
The equations for preparation K2MnO4
Catalyst
normal
Temperature
temperature
Pressure
normal
Other conditions
normal
Catalyst
normal
Temperature
temperature
Pressure
normal
Other conditions
normal
Catalyst
normal
Temperature
temperature
Pressure
normal
Other conditions
normal
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