Equation Result #1
|Hydrogen||Hydroxylamine; Hydroxyamine||ammonium hydroxide|
|Nguyên - Phân tử khối (g/mol)|
|Khối lượng (g)|
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance NH4OH (ammonium hydroxide), appearing at the end of the reaction.
Or if any of the following reactant substances NH2OH (Hydroxylamine; Hydroxyamine), disappearing
Hydrogen atoms are prepared from the reaction of Zn and concentrated NaOH
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C6H5NO2 + 6H => C6H5NH2 + 2H2O C6H5NO2 + 6H => C6H5NH2 + 2H2O NH4NO3 + 2H => H2O + NH4NO2 View all equations with H as reactant
Hydroxylamine; Hydroxyamine2H + NH2OH => NH4OH H2SO4 + 2NH2OH => (NH3OH)2SO4 HClO4 + NH2OH => NH3OHClO4 View all equations with NH2OH as reactant
Hydroxylamine; HydroxyamineC2H5ONa + (NH3OH)Cl => C2H5OH + NaCl + NH2OH 2H2O + 4H + Na2N2O2 => 2NaOH + 2NH2OH View all equations with NH2OH as product