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|iron(ii) chloride||potassium hydroxide||potassium chloride|
|Nguyên - Phân tử khối (g/mol)|
|Khối lượng (g)|
No information found for this chemical equation
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
In a full sentence, you can also say FeCl2 (iron(ii) chloride) reacts with KOH (potassium hydroxide) and produce KCl (potassium chloride) and Fe(OH)2 ()
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance Fe(OH)2, appearing at the end of the reaction.
Or if any of the following reactant substances KOH (potassium hydroxide), disappearing
We no further information about this chemical reactions.
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iron(ii) chlorideFeCl2 → Cl2 + Fe FeCl2 + 4HNO3 → H2O + 2HCl + NO2 + Fe(NO3)3 3FeCl2 + 4HNO3 → 2H2O + NO + Fe(NO3)3 + 2FeCl3 View all equations with FeCl2 as reactant
potassium hydroxide2KOH + Mg(NO3)2 → 2KNO3 + Mg(OH)2 KOH + FeCl3 → KCl + Fe(OH)3 KOH + HCOOCH3 → CH3OH + HCOOK View all equations with KOH as reactant
potassium hydroxide3C2H4 + 4H2O + 2KMnO4 → 2KOH + 2MnO2 + 3C2H4(OH)2 H2O + K2O → 2KOH 2NaOH + K2HPO4 → 2KOH + Na2HPO4 View all equations with KOH as product
potassium hydroxide2NaOH + K2HPO4 → 2KOH + Na2HPO4 3C2H4 + 4H2O + 2KMnO4 → 2KOH + 2MnO2 + 3C2H4(OH)2 H2O + K2O → 2KOH View all equations with KOH as product
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