Table of Content
|(dung dịch đậm đặc)||(lỏng)||(dung dịch)||(khí)||(kết tủa)|
|(không màu, không mùi)||(không màu)||(không màu)||(lục xám)|
|Nguyên - Phân tử khối (g/mol)|
|Khối lượng (g)|
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
NH3 reacts with H2Cr2O7
In a full sentence, you can also say NH3 (ammonia) reacts with H2Cr2O7 () and produce KOH (potassium hydroxide) and N2 (nitrogen) and Cr(OH)3 ()
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance Cr(OH)3, appearing at the end of the reaction.
Or if any of the following reactant substances H2Cr2O7, disappearing
We no further information about this chemical reactions.
ammonia2NH3 + 3PbO → 3H2O + N2 + 3Pb 2AgNO3 + H2O + HCHO + 3NH3 → 2Ag + 2NH4NO3 + HCOONH4 2NH3 + CO2 → (NH2)2CO + H2O View all equations with NH3 as reactant
2NH3 + H2Cr2O7 → 2KOH + N2 + 2Cr(OH)3 H2O + H2Cr2O7 → 2H2CrO4 2H2O + H2Cr2O7 → 2H3O + (Cr2O7) View all equations with H2Cr2O7 as reactant
H2O + 2CrO3 → H2Cr2O7 4H2O + 2CrCl3 + HClO3 → 7HCl + H2Cr2O7 H2O + 2Cr2O3 → H2Cr2O7 View all equations with H2Cr2O7 as product
H2O + 2CrO3 → H2Cr2O7 2H2O + 3H2SO4 + 5Cr2O3 + 6NaBrO3 → 3Br2 + 3Na2SO4 + 5H2Cr2O7 4H2O + 2CrCl3 + HClO3 → 7HCl + H2Cr2O7 View all equations with H2Cr2O7 as product