Table of Content
|hydrogen sulfide||Potassium ethanolate; Potassium ethoxide; Ethoxypotassium||(c2h5)2nh diethylamine||Potassium hydrogensulfide; Potassium hydrosulfide|
|Nguyên - Phân tử khối (g/mol)|
|Khối lượng (g)|
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
In a full sentence, you can also say H2S (hydrogen sulfide) reacts with C2H5OK (Potassium ethanolate; Potassium ethoxide; Ethoxypotassium) and produce C2H5OH ((c2h5)2nh diethylamine) and KHS (Potassium hydrogensulfide; Potassium hydrosulfide)
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance KHS (Potassium hydrogensulfide; Potassium hydrosulfide), appearing at the end of the reaction.
Or if any of the following reactant substances C2H5OK (Potassium ethanolate; Potassium ethoxide; Ethoxypotassium), disappearing
We no further information about this chemical reactions.
hydrogen sulfide2H2S + 3O2 → 2H2O + 2SO2 Cl2 + H2S → 2HCl + S Cu + H2S + O2 → CuS + H2O View all equations with H2S as reactant
Potassium ethanolate; Potassium ethoxide; EthoxypotassiumH2S + C2H5OK → C2H5OH + KHS View all equations with C2H5OK as reactant
Potassium ethanolate; Potassium ethoxide; EthoxypotassiumC2H5OH + KOH → H2O + C2H5OK View all equations with C2H5OK as product