Table of Content
Cl2 | + | 2KRuO4 | → | 2KCl | + | 2RuO4 | |
chlorine | Potassium perruthenate | potassium chloride | Ruthenium tetraoxide; Ruthenium(VIII)tetraoxide | ||||
(bão hòa) | (dung dịch pha loãng) | ||||||
1 | 2 | 2 | 2 | Hệ số | |||
Nguyên - Phân tử khối (g/mol) | |||||||
Số mol | |||||||
Khối lượng (g) |
No information found for this chemical equation
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
In a full sentence, you can also say Cl2 (chlorine) reacts with KRuO4 (Potassium perruthenate) and produce KCl (potassium chloride) and RuO4 (Ruthenium tetraoxide; Ruthenium(VIII)tetraoxide)
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance RuO4 (Ruthenium tetraoxide; Ruthenium(VIII)tetraoxide), appearing at the end of the reaction.
Or if any of the following reactant substances KRuO4 (Potassium perruthenate), disappearing
We no further information about this chemical reactions.
chlorine
Cl2 + 2Na → 2NaCl Cl2 + C3H8 → HCl + C3H7Cl Cl2 + H2O → HCl + HClO View all equations with Cl2 as reactantPotassium perruthenate
Cl2 + 2KRuO4 → 2KCl + 2RuO4 View all equations with KRuO4 as reactantPotassium perruthenate
4KOH + 4RuO4 → 2H2O + O2 + 4KRuO4 H2O + KClO + 2K2RuO4 → KCl + 2KOH + 2KRuO4 Cl2 + 2K2RuO4 → 2KCl + 2KRuO4 View all equations with KRuO4 as productPotassium perruthenate
H2O + KClO + 2K2RuO4 → KCl + 2KOH + 2KRuO4 4KOH + 4RuO4 → 2H2O + O2 + 4KRuO4 Cl2 + 2K2RuO4 → 2KCl + 2KRuO4 View all equations with KRuO4 as productInteresting Information Only Few People Knows
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