Table of Content
|chlorine||Potassium perruthenate||potassium chloride||Ruthenium tetraoxide; Ruthenium(VIII)tetraoxide|
|(bão hòa)||(dung dịch pha loãng)|
|Nguyên - Phân tử khối (g/mol)|
|Khối lượng (g)|
No information found for this chemical equation
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
In a full sentence, you can also say Cl2 (chlorine) reacts with KRuO4 (Potassium perruthenate) and produce KCl (potassium chloride) and RuO4 (Ruthenium tetraoxide; Ruthenium(VIII)tetraoxide)
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance RuO4 (Ruthenium tetraoxide; Ruthenium(VIII)tetraoxide), appearing at the end of the reaction.
Or if any of the following reactant substances KRuO4 (Potassium perruthenate), disappearing
We no further information about this chemical reactions.
chlorineCl2 + 2Na → 2NaCl Cl2 + C3H8 → HCl + C3H7Cl Cl2 + H2O → HCl + HClO View all equations with Cl2 as reactant
Potassium perruthenateCl2 + 2KRuO4 → 2KCl + 2RuO4 View all equations with KRuO4 as reactant
Potassium perruthenate4KOH + 4RuO4 → 2H2O + O2 + 4KRuO4 H2O + KClO + 2K2RuO4 → KCl + 2KOH + 2KRuO4 Cl2 + 2K2RuO4 → 2KCl + 2KRuO4 View all equations with KRuO4 as product