Table of Content
|sodium chlorate||Praseodymium(III,IV) oxide||sodium chloride||Praseodymium(IV) oxide; Praseodymium(IV)dioxide|
|Nguyên - Phân tử khối (g/mol)|
|Khối lượng (g)|
Temperature: < 250
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
In a full sentence, you can also say NaClO3 (sodium chlorate) reacts with Pr6O11 (Praseodymium(III,IV) oxide) and produce NaCl (sodium chloride) and PrO2 (Praseodymium(IV) oxide; Praseodymium(IV)dioxide)
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance PrO2 (Praseodymium(IV) oxide; Praseodymium(IV)dioxide), appearing at the end of the reaction.
Or if any of the following reactant substances Pr6O11 (Praseodymium(III,IV) oxide), disappearing
We no further information about this chemical reactions.
sodium chlorate2NaClO3 → 2NaCl + 3O2 H2SO4 + SO2 + 2NaClO3 → 2ClO2 + 2NaHSO4 6ClF3 + 2NaClO3 → 2NaCl + 3ClF5 + 3ClO2F View all equations with NaClO3 as reactant
Praseodymium(III,IV) oxideNaClO3 + 3Pr6O11 → NaCl + 18PrO2 View all equations with Pr6O11 as reactant
Praseodymium(III,IV) oxide11O2 + 12Pr → 2Pr6O11 View all equations with Pr6O11 as product