Table of Content
K2Cr2O7 | + | 2KOH | → | H2O | + | 2K2CrO4 | |
Potassium dichromate; Potassium bichromate; Dichromic acid dipotassium salt | potassium hydroxide | water | |||||
(dung dịch) | (đậm đặc) | (lỏng) | (dung dịch) | ||||
(da cam) | (không màu) | (không màu) | (vàng) | ||||
1 | 2 | 1 | 2 | Hệ số | |||
Nguyên - Phân tử khối (g/mol) | |||||||
Số mol | |||||||
Khối lượng (g) |
No information found for this chemical equation
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
K2Cr2O7 reacts with NaOH
In a full sentence, you can also say K2Cr2O7 (Potassium dichromate; Potassium bichromate; Dichromic acid dipotassium salt) reacts with KOH (potassium hydroxide) and produce H2O (water) and K2CrO4 ()
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance K2CrO4, appearing at the end of the reaction.
Or if any of the following reactant substances KOH (potassium hydroxide), disappearing
We no further information about this chemical reactions.
Potassium dichromate; Potassium bichromate; Dichromic acid dipotassium salt
H2SO4 + K2Cr2O7 → H2O + CrO3 + K2SO4 5K2Cr2O7 + 6P → 5K2O + 3P2O5 + 5Cr2O3 K2Cr2O7 + S → Cr2O3 + K2SO4 View all equations with K2Cr2O7 as reactantpotassium hydroxide
2KOH + Mg(NO3)2 → 2KNO3 + Mg(OH)2 KOH + FeCl3 → KCl + Fe(OH)3 2KOH + CH3NH3HCO3 → H2O + K2CO3 + CH3NH2 View all equations with KOH as reactantpotassium hydroxide
2NaOH + K2HPO4 → 2KOH + Na2HPO4 3C2H4 + 4H2O + 2KMnO4 → 2KOH + 2MnO2 + 3C2H4(OH)2 H2O + K2O → 2KOH View all equations with KOH as productpotassium hydroxide
2NaOH + K2HPO4 → 2KOH + Na2HPO4 H2O + K2O → 2KOH 3C2H4 + 4H2O + 2KMnO4 → 2KOH + 2MnO2 + 3C2H4(OH)2 View all equations with KOH as productInteresting Information Only Few People Knows
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