Table of Content
H2SO4 | + | NaBr | → | NaHSO4 | + | HBr | |
sulfuric acid | sodium bromide | hydrobromic acid | |||||
1 | 1 | 1 | 1 | Hệ số | |||
Nguyên - Phân tử khối (g/mol) | |||||||
Số mol | |||||||
Khối lượng (g) |
Temperature: temperature
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
In a full sentence, you can also say H2SO4 (sulfuric acid) reacts with NaBr (sodium bromide) and produce NaHSO4 () and HBr (hydrobromic acid)
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance HBr (hydrobromic acid), appearing at the end of the reaction.
Or if any of the following reactant substances NaBr (sodium bromide), disappearing
We no further information about this chemical reactions.
sulfuric acid
10FeO + 18H2SO4 + 2KMnO4 → 5Fe2(SO4)3 + 18H2O + 2MnSO4 + K2SO4 H2SO4 + Na2SO3 → H2O + Na2SO4 + SO2 8H2SO4 + 2KMnO4 + 10NaBr → 5Br2 + 8H2O + 2MnSO4 + 5Na2SO4 + K2SO4 View all equations with H2SO4 as reactantsodium bromide
8H2SO4 + 2KMnO4 + 10NaBr → 5Br2 + 8H2O + 2MnSO4 + 5Na2SO4 + K2SO4 Cl2 + 2NaBr → Br2 + 2NaCl 2H2SO4 + MnO2 + 2NaBr → Br2 + 2H2O + MnSO4 + Na2SO4 View all equations with NaBr as reactantsodium bromide
NaOH + C6H5Br → C6H5ONa + H2O + NaBr Br2 + 2NaI → I2 + 2NaBr 2Br2 + 8NaOH + CrBr2 → 4H2O + Na2CrO4 + 6NaBr View all equations with NaBr as productsodium bromide
NaOH + C6H5Br → C6H5ONa + H2O + NaBr Br2 + 2NaI → I2 + 2NaBr 2Br2 + 8NaOH + CrBr2 → 4H2O + Na2CrO4 + 6NaBr View all equations with NaBr as productInteresting Information Only Few People Knows
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