Table of Content
CO | + | H2O | + | PdCl2 | → | 2HCl | + | CO2 | + | Pd | |
carbon monoxide | water | palladium(ii) chloride | hydrogen chloride | carbon dioxide | Pd; Palladium | ||||||
(khí) | (lỏng) | (lỏng) | (lỏng) | (khí) | (rắn) | ||||||
(không màu) | (không màu) | (màu đỏ sẫm) | (không màu) | (không màu) | (ánh bạc trắng) | ||||||
1 | 1 | 1 | 2 | 1 | 1 | Hệ số | |||||
Nguyên - Phân tử khối (g/mol) | |||||||||||
Số mol | |||||||||||
Khối lượng (g) |
No information found for this chemical equation
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
In a full sentence, you can also say CO (carbon monoxide) reacts with H2O (water) reacts with PdCl2 (palladium(ii) chloride) and produce HCl (hydrogen chloride) and CO2 (carbon dioxide) and Pd (Pd; Palladium)
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance Pd (Pd; Palladium), appearing at the end of the reaction.
Or if any of the following reactant substances PdCl2 (palladium(ii) chloride), disappearing
We no further information about this chemical reactions.
carbon monoxide
CO + H2O + PdCl2 → 2HCl + CO2 + Pd 2CO + O2 → 2CO2 y-xCO + FexOy → FeO + y-xCO2 View all equations with CO as reactantwater
2H2O + 2NaCl → Cl2 + H2 + 2NaOH 2H2O + 2K + CuSO4 → Cu(OH)2 + H2 + K2SO4 2H2O → 2H2 + O2 View all equations with H2O as reactantpalladium(ii) chloride
CO + H2O + PdCl2 → 2HCl + CO2 + Pd CO + H2O + PdCl2 → 2HCl + CO2 + Pd PdCl2 + HCOOH → 2HCl + CO2 + Pd View all equations with PdCl2 as reactantpalladium(ii) chloride
PdCl2.2H2O → 2H2O + PdCl2 Cl2 + Pd → PdCl2 2HCl + Pd(OH)2 → 2H2O + PdCl2 View all equations with PdCl2 as productpalladium(ii) chloride
PdCl2.2H2O → 2H2O + PdCl2 Cl2 + Pd → PdCl2 2HCl + Pd(OH)2 → 2H2O + PdCl2 View all equations with PdCl2 as productpalladium(ii) chloride
PdCl2.2H2O → 2H2O + PdCl2 Cl2 + Pd → PdCl2 2HCl + Pd(OH)2 → 2H2O + PdCl2 View all equations with PdCl2 as productInteresting Information Only Few People Knows