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C6H5OH + O2 = H2O + CO2 | Balanced | Chemical Reaction Details

phenol + oxygen = water + carbon dioxide |

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Table of Content

C6H5OH + 4O23H2O + 6CO2
phenol oxygen water carbon dioxide
(lỏng) (khí)
1 4 3 6 Hệ số
Nguyên - Phân tử khối (g/mol)
Số mol
Khối lượng (g)

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Further information about equation C6H5OH + 4O2 → 3H2O + 6CO2

What is reaction condition of C6H5OH (phenol) reacts with O2 (oxygen) ?

No information found for this chemical equation

Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.

How reactions can happened and produce H2O (water) and CO2 (carbon dioxide) ?

In a full sentence, you can also say C6H5OH (phenol) reacts with O2 (oxygen) and produce H2O (water) and CO2 (carbon dioxide)

Phenomenon after C6H5OH (phenol) reacts with O2 (oxygen)

Click to see equation's phenomenon

What are other important informations you should know about reaction

We no further information about this chemical reactions.

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Further questions related to chemical reactions C6H5OH + 4O2 → 3H2O + 6CO2

Questions related to reactant C6H5OH (phenol)

What are the chemical and physical characteristic of C6H5OH (phenol)? What are the chemical reactions that have C6H5OH (phenol) as reactant?

Questions related to reactant O2 (oxygen)

What are the chemical and physical characteristic of O2 (oxygen)? What are the chemical reactions that have O2 (oxygen) as reactant?

Questions related to product H2O (water)

What are the chemical and physical characteristic of H2O (oxygen)? What are the chemical reactions that have H2O (water) as product?

Questions related to product CO2 (carbon dioxide)

What are the chemical and physical characteristic of CO2 (oxygen)? What are the chemical reactions that have CO2 (carbon dioxide) as product?

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C6H5OH + 4O2 = 3H2O + 6CO2 | Chemical Equation

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