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(NH4)2SO4 + Ba(OH)2 → H2O + 2NH3 + BaSO4 | Phương Trình Phản Ứng Hóa Học
(NH4)2SO4 | ammonium sulfate | solid + Ba(OH)2 | barium hydroxide | solid = H2O | water | solid + NH3 | ammonia | solid + BaSO4 | barium sulfate | solid | Temperature: temperature, Other Condition excess chlorine
Introduce
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Detailed information about the equation
Reaction conditions when applied (NH4)2SO4 + Ba(OH)2
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Detailed information on the reactants
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Detailed information about the products of the reaction
Detailed information about the equation
Reaction conditions when applied (NH4)2SO4 + Ba(OH)2
- Catalyst: not available
- Temperature: normal
- Pressure: normal
- Other conditions: not available
Reaction process (NH4)2SO4 + Ba(OH)2
Process: (NH4)2SO4 plus Ba(OH)2
Note: not available
The result of the reaction (NH4)2SO4 + Ba(OH)2
The phenomenon: White precipitate (BaSO4) is formed and ammonia gas (NH3) is emitted with a characteristic pungent smell
Detailed information on the reactants
Information about (NH4)2SO4 (ammonium sulfate)
Information about Ba(OH)2 (barium hydroxide)
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Detailed information about the products of the reaction
Information about H2O (water)
Information about NH3 (ammonia)
Information about BaSO4 (barium sulfate)
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The equations for preparation (NH4)2SO4
Catalyst
normal
Temperature
normal
Pressure
normal
Other conditions
normal
Catalyst
normal
Temperature
normal
Pressure
normal
Other conditions
normal
Catalyst
normal
Temperature
temperature
Pressure
normal
Other conditions
normal
The equations for preparation Ba(OH)2
Catalyst
normal
Temperature
normal
Pressure
normal
Other conditions
normal
Catalyst
normal
Temperature
normal
Pressure
normal
Other conditions
normal
Catalyst
normal
Temperature
normal
Pressure
normal
Other conditions
normal
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