Equation Result #1
|sulfur dioxide||barium hydroxide|
|(không màu)||(không màu)||(không màu)|
|Nguyên - Phân tử khối (g/mol)|
|Khối lượng (g)|
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance Ba(HSO3)2, appearing at the end of the reaction.
Or if any of the following reactant substances Ba(OH)2 (barium hydroxide), disappearing
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sulfur dioxide2SO2 + Ba(OH)2 => Ba(HSO3)2 2H2O + 2KMnO4 + 5SO2 => 2H2SO4 + 2MnSO4 + K2SO4 H2O + SO2 => H2SO3 View all equations with SO2 as reactant
barium hydroxide2SO2 + Ba(OH)2 => Ba(HSO3)2 2(NH4)3PO4 + 3Ba(OH)2 => 6H2O + 6NH3 + Ba3(PO4)2 2Cl2 + 2Ba(OH)2 => BaCl2 + 2H2O + Ba(ClO)2 View all equations with Ba(OH)2 as reactant