Table of Content
|oxygen||lead(ii) sulfide||sulfur dioxide||lead(ii) oxide|
|Nguyên - Phân tử khối (g/mol)|
|Khối lượng (g)|
No information found for this chemical equation
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
In a full sentence, you can also say O2 (oxygen) reacts with PbS (lead(ii) sulfide) and produce SO2 (sulfur dioxide) and PbO (lead(ii) oxide)
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance PbO (lead(ii) oxide), appearing at the end of the reaction.
Or if any of the following reactant substances PbS (lead(ii) sulfide), disappearing
We no further information about this chemical reactions.
oxygen2Mg + O2 → 2MgO C + O2 → CO2 4Al + 3O2 → 2Al2O3 View all equations with O2 as reactant
lead(ii) sulfide4H2O2 + PbS → 4H2O + PbSO4 4O3 + PbS → 4O2 + PbSO4 4NaClO + PbS → 4NaCl + PbSO4 View all equations with PbS as reactant
lead(ii) sulfideH2S + Pb(NO3)2 → 2HNO3 + PbS Na2S + Pb(NO3)2 → 2NaNO3 + PbS H2S + Pb(NO3)2 → 2HNO3 + PbS View all equations with PbS as product