Table of Content
13O2 | + | 2C4H10 | → | 10H2O | + | 8CO2 | |
oxygen | butane | water | carbon dioxide | ||||
13 | 2 | 10 | 8 | Hệ số | |||
Nguyên - Phân tử khối (g/mol) | |||||||
Số mol | |||||||
Khối lượng (g) |
No information found for this chemical equation
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
In a full sentence, you can also say O2 (oxygen) reacts with C4H10 (butane) and produce H2O (water) and CO2 (carbon dioxide)
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance CO2 (carbon dioxide), appearing at the end of the reaction.
Or if any of the following reactant substances C4H10 (butane), disappearing
We no further information about this chemical reactions.
oxygen
2H2S + 3O2 → 2H2O + 2SO2 C + O2 → CO2 4Al + 3O2 → 2Al2O3 View all equations with O2 as reactantbutane
C4H10 → CH3CH=CHCH3 + H2 C4H10 → C2H4 + C2H6 5O2 + 2C4H10 → 4CH3COOH + 2H2O View all equations with C4H10 as reactantbutane
Na + 2C2H5Cl → 2NaCl + C4H10 C4H6 + 2H2 → C4H10 CH3Cl + 2Na + C3H7Cl → 2NaCl + C4H10 View all equations with C4H10 as productbutane
Na + 2C2H5Cl → 2NaCl + C4H10 C4H6 + 2H2 → C4H10 CH3Cl + 2Na + C3H7Cl → 2NaCl + C4H10 View all equations with C4H10 as productInteresting Information Only Few People Knows
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