Table of Content
5O2 | + | 2C4H10 | → | 4CH3COOH | + | 2H2O | |
oxygen | butane | ethanoic acid | water | ||||
(khí) | (khí) | (lỏng) | (lỏng) | ||||
(không màu) | (không màu) | (không màu) | (không màu) | ||||
5 | 2 | 4 | 2 | Hệ số | |||
Nguyên - Phân tử khối (g/mol) | |||||||
Số mol | |||||||
Khối lượng (g) |
Temperature: temperature Solvent: Mn2+
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
C4H10 is oxidized by oxygen in the air
In a full sentence, you can also say O2 (oxygen) reacts with C4H10 (butane) and produce CH3COOH (ethanoic acid) and H2O (water)
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance H2O (water), appearing at the end of the reaction.
Or if any of the following reactant substances C4H10 (butane), disappearing
We no further information about this chemical reactions.
oxygen
4Al + 3O2 → 2Al2O3 2H2S + 3O2 → 2H2O + 2SO2 2Mg + O2 → 2MgO View all equations with O2 as reactantbutane
C4H10 → CH3CH=CHCH3 + H2 C4H10 → C2H4 + C2H6 5O2 + 2C4H10 → 4CH3COOH + 2H2O View all equations with C4H10 as reactantbutane
Na + 2C2H5Cl → 2NaCl + C4H10 C4H6 + 2H2 → C4H10 CH3Cl + 2Na + C3H7Cl → 2NaCl + C4H10 View all equations with C4H10 as productbutane
Na + 2C2H5Cl → 2NaCl + C4H10 C4H6 + 2H2 → C4H10 CH3Cl + 2Na + C3H7Cl → 2NaCl + C4H10 View all equations with C4H10 as productInteresting Information Only Few People Knows