Table of Content
6nO2 | + | (C6H10O5)n | → | 5nH2O | + | 6nCO2 | |
oxygen | water | carbon dioxide | |||||
(khí) | (rắn) | (lỏng) | (khí) | ||||
(không màu) | (trắng) | (không màu) | (không màu) | ||||
6n | 1 | 5n | 6n | Hệ số | |||
Nguyên - Phân tử khối (g/mol) | |||||||
Số mol | |||||||
Khối lượng (g) |
Temperature: t0
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
Burning the starch in the air
In a full sentence, you can also say O2 (oxygen) reacts with (C6H10O5)n () and produce H2O (water) and CO2 (carbon dioxide)
We no further information about this chemical reactions.
oxygen
4Al + 3O2 → 2Al2O3 2H2S + 3O2 → 2H2O + 2SO2 C + O2 → CO2 View all equations with O2 as reactantnH2O + (C6H10O5)n → nC6H12O6 6nO2 + (C6H10O5)n → 5nH2O + 6nCO2 nH2O + (C6H10O5)n → nC6H12O6 View all equations with (C6H10O5)n as reactant
5nH2O + 6nCO2 → 6nO2 + (C6H10O5)n View all equations with (C6H10O5)n as product
5nH2O + 6nCO2 → 6nO2 + (C6H10O5)n View all equations with (C6H10O5)n as product
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