NaOH + Be(OH)2 = H2O + Na2BeO2 | Chemical Equation Details
sodium hydroxide + beryllium hydroxide = water + Sodium beryllate | Temperature: 200 - 300
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Equation Result #1
| 2NaOH | + | Be(OH)2 | → | 2H2O | + | Na2BeO2 | |
| sodium hydroxide | beryllium hydroxide | water | Sodium beryllate | ||||
| 2 | 1 | 2 | 1 | Hệ số | |||
| Nguyên - Phân tử khối (g/mol) | |||||||
| Số mol | |||||||
| Khối lượng (g) |
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Click here to find more information about this equationEquations with NaOH as reactant
sodium hydroxide
Equations with Be(OH)2 as reactant
beryllium hydroxide
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Equations with Be(OH)2 as product
beryllium hydroxide
Equations with Be(OH)2 as product
beryllium hydroxide
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