Table of Content
2NaBH4 | → | 3H2 | + | 2NaH | + | 2B | |
sodium borohydride | hydrogen | sodium hydride | boron | ||||
2 | 3 | 2 | 2 | Hệ số | |||
Nguyên - Phân tử khối (g/mol) | |||||||
Số mol | |||||||
Khối lượng (g) |
Temperature: > 450
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
In a full sentence, you can also say NaBH4 (sodium borohydride) and produce H2 (hydrogen) and NaH (sodium hydride) and B (boron)
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance B (boron), appearing at the end of the reaction.
Or if any of the following reactant substances NaBH4 (sodium borohydride), disappearing
We no further information about this chemical reactions.
sodium borohydride
2CH3CHO + H2SO4 + 2NaBH4 → 2C2H5OH + Na2SO4 + 2BH3 H2SO4 + 2NaBH4 → 2H2 + Na2SO4 + B2H6 AlCl3 + 3NaBH4 → 3NaCl + Al(BH4)3 View all equations with NaBH4 as reactantsodium borohydride
2B2H6 + Na2Hg → Hg + NaBH4 + NaB3H8 7H2 + 2Na + B2O3 → 3H2O + 2NaBH4 4NaH + B(OCH3)3 → NaBH4 + 3NaOCH3 View all equations with NaBH4 as productsodium borohydride
7H2 + 2Na + B2O3 → 3H2O + 2NaBH4 2B2H6 + Na2Hg → Hg + NaBH4 + NaB3H8 4NaH + B(OCH3)3 → NaBH4 + 3NaOCH3 View all equations with NaBH4 as productsodium borohydride
7H2 + 2Na + B2O3 → 3H2O + 2NaBH4 2B2H6 + Na2Hg → Hg + NaBH4 + NaB3H8 4NaH + B(OCH3)3 → NaBH4 + 3NaOCH3 View all equations with NaBH4 as productInteresting Information Only Few People Knows