Table of Content
11Cl2 | + | B4H10 | → | 10HCl | + | 4BCl3 | |
chlorine | tetraborane | hydrogen chloride | Boron trichloride; Trichloroboron; Trichloroborane | ||||
11 | 1 | 10 | 4 | Hệ số | |||
Nguyên - Phân tử khối (g/mol) | |||||||
Số mol | |||||||
Khối lượng (g) |
No information found for this chemical equation
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
In a full sentence, you can also say Cl2 (chlorine) reacts with B4H10 (tetraborane) and produce HCl (hydrogen chloride) and BCl3 (Boron trichloride; Trichloroboron; Trichloroborane)
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance BCl3 (Boron trichloride; Trichloroboron; Trichloroborane), appearing at the end of the reaction.
Or if any of the following reactant substances B4H10 (tetraborane), disappearing
We no further information about this chemical reactions.
chlorine
Cl2 + 2Na → 2NaCl Cl2 + C3H8 → HCl + C3H7Cl 5Cl2 + 2P → 2PCl5 View all equations with Cl2 as reactanttetraborane
11Cl2 + B4H10 → 10HCl + 4BCl3 View all equations with B4H10 as reactant
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