Table of Content
CH3COOH | + | NaClO | → | CH3COONa | + | HClO | |
ethanoic acid | hypochlorous acid | ||||||
(dung dịch) | (dung dịch) | (rắn) | (dung dịch) | ||||
(không màu) | |||||||
1 | 1 | 1 | 1 | Hệ số | |||
Nguyên - Phân tử khối (g/mol) | |||||||
Số mol | |||||||
Khối lượng (g) |
No information found for this chemical equation
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
CH3COOH reacts with NaClO
In a full sentence, you can also say CH3COOH (ethanoic acid) reacts with NaClO () and produce CH3COONa () and HClO (hypochlorous acid)
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance HClO (hypochlorous acid), appearing at the end of the reaction.
Or if any of the following reactant substances NaClO, disappearing
We no further information about this chemical reactions.
ethanoic acid
2CH3COOH + Cu(OH)2 → 2H2O + (CH3COO)2Cu 2CH3COOH + Mg(OH)2 → 2H2O + (CH3COO)2Mg 2CH3COOH + Na2CO3 → 2CH3COONa + H2O + CO2 View all equations with CH3COOH as reactant2NaClO → 2NaCl + O2 3NaClO + 10NaOH + 2CrCl3 → 5H2O + 9NaCl + 2Na2CrO4 H2SO4 + 2KI + 8NaClO → H2O + I2 + 8NaCl + K2SO4 View all equations with NaClO as reactant
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