Table of Content
2C6H5OH | + | 2Na | → | 2C6H5ONa | + | H2 | |
phenol | sodium | hydrogen | |||||
(lỏng) | (rắn) | (lỏng) | (khí) | ||||
(không màu) | (trắng) | (không màu) | (không màu) | ||||
2 | 2 | 2 | 1 | Hệ số | |||
Nguyên - Phân tử khối (g/mol) | |||||||
Số mol | |||||||
Khối lượng (g) |
No information found for this chemical equation
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
In a full sentence, you can also say C6H5OH (phenol) reacts with Na (sodium) and produce C6H5ONa () and H2 (hydrogen)
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance H2 (hydrogen), appearing at the end of the reaction.
Or if any of the following reactant substances Na (sodium), disappearing
We no further information about this chemical reactions.
phenol
3Br2 + C6H5OH → 3HBr + (Br)3C6H2OH 2C6H5OH + 2Na → 2C6H5ONa + H2 C6H5OH + Na → C6H5ONa + 1/2H2 View all equations with C6H5OH as reactantsodium
2H2O + 2Na → H2 + 2NaOH Cl2 + 2Na → 2NaCl Na + C2H5COOH → H2 + C2H5COONa View all equations with Na as reactantsodium
C + 6NaOH → 3H2 + 2Na + 2Na2CO3 2NaCl → Cl2 + 2Na 4NaOH → 2H2O + 4Na + O2 View all equations with Na as productsodium
C + 6NaOH → 3H2 + 2Na + 2Na2CO3 2NaCl → Cl2 + 2Na 4NaOH → 2H2O + 4Na + O2 View all equations with Na as productInteresting Information Only Few People Knows