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C4H9Cl = tat-ca | Chemical Equation Balancer

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Equation Result #1


NaOH + C4H9ClNaCl + CH3CH2CH2CH2OH
sodium hydroxide sodium chloride butan-1-ol
(dung dịch) (khí) (rắn) (lỏng)
(không màu) (trắng)
1 1 1 1 Hệ số
Nguyên - Phân tử khối (g/mol)
Số mol
Khối lượng (g)

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Condition

No information found for this chemical equation

How reaction can happen

C4H9Cl reacts with NaOH

Phenomenon

This equation does not have any specific information about phenomenon.

In this case, you just need to observe to see if product substance C4H9OH (butan-1-ol), appearing at the end of the reaction.

Or if any of the following reactant substances C4H9Cl, disappearing

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Extra information about substances that equation use

Reaction of NaOH (natri hidroxit) react with C4H9Cl (sec-butyl clorua) produce NaCl (Natri Clorua)

Reaction that produces substance NaOH (natri hidroxit) (sodium hydroxide)

2H2O + 2Na => H2 + 2NaOH 2H2O + 2NaCl => Cl2 + H2 + 2NaOH Ca(OH)2 + NaHCO3 => CaCO3 + H2O + NaOH

Reaction that produces substance C4H9Cl (sec-butyl clorua) ()

Cl2 + C4H10 => HCl + C4H9Cl

Reaction that produces substance NaCl (Natri Clorua) (sodium chloride)

Cl2 + 2Na => 2NaCl HCl + NaOH => H2O + NaCl 2HCl + Na2CO3 => H2O + 2NaCl + CO2

Reaction that produces substance CH3CH2CH2CH2OH (n-butanol) (butan-1-ol)

NaOH + C4H9Cl => NaCl + CH3CH2CH2CH2OH CH3CH=CHCH3 + H2O => CH3CH2CH2CH2OH

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