Equation Result #1
|(Không màu)||(Không màu)||(Không màu)|
|Nguyên - Phân tử khối (g/mol)|
|Khối lượng (g)|
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance C2H6 (ethane), appearing at the end of the reaction.
Or if any of the following reactant substances C4H10 (butane), disappearing
At high temperatures and with a suitable catalyst, apart from hydrogen being separated, alkane can also be breaken down to create into smaller molecules
We have been working with Google to develop an advanced search with results filted with chemistry topic onlyClick here to find more information about this equation
butaneC4H10 => CH3CH=CHCH3 + H2 C4H10 => C2H4 + C2H6 5O2 + 2C4H10 => 4CH3COOH + 2H2O View all equations with C4H10 as reactant
butaneNa + 2C2H5Cl => 2NaCl + C4H10 C4H6 + 2H2 => C4H10 CH3Cl + 2Na + C3H7Cl => 2NaCl + C4H10 View all equations with C4H10 as product