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Au F2 = AuF3 | Chemical Equation Balancer

fluorine = gold(iii) fluoride

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Equation Result #1

2Au + 3F22AuF3
gold fluorine gold(iii) fluoride
2 3 2 Hệ số
Nguyên - Phân tử khối (g/mol)
Số mol
Khối lượng (g)

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Further information about equation 2Au + 3F2 → 2AuF3

What is reaction condition of Au (gold) reacts with F2 (fluorine) ?

Temperature: 300 - 400°C

Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.

How reactions can happened and produce AuF3 (gold(iii) fluoride) ?

Phenomenon after Au (gold) reacts with F2 (fluorine)

Click to see equation's phenomenon

What are other important informations you should know about reaction

We no further information about this chemical reactions.

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Further questions related to chemical reactions 2Au + 3F2 → 2AuF3

Questions related to reactant Au (gold)

What are the chemical and physical characteristic of Au (gold)? What are the chemical reactions that have Au (gold) as reactant?

Questions related to reactant F2 (fluorine)

What are the chemical and physical characteristic of F2 (fluorine)? What are the chemical reactions that have F2 (fluorine) as reactant?

Questions related to product AuF3 (gold(iii) fluoride)

What are the chemical and physical characteristic of AuF3 (fluorine)? What are the chemical reactions that have AuF3 (gold(iii) fluoride) as product?
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Extra information about substances that equation use

Reaction of Au (vàng) react with F2 (flo) produce AuF3 (Vàng(III) florua) ,temperature condition 300 - 400

Reaction that produces substance Au (vàng) (gold)

Zn + 2Na[Au(CN)2] → 2Au + Na2[Zn(CN)4] 3FeSO4 + AuCl3 → Au + Fe2(SO4)3 + FeCl3 3H2S + 2HAuCl4 → 2Au + 8HCl + 3S

Reaction that produces substance F2 (flo) (fluorine)

KF → F2 + K 2HF → F2 + H2 XeF6 → F2 + XeF4

Reaction that produces substance AuF3 (Vàng(III) florua) (gold(iii) fluoride)

2Au + 3F2 → 2AuF3 3F2 + 2AuCl3 → 3Cl2 + 2AuF3

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