# K[PtF6] = F2 KF PtF4 | Chemical Equation Balancer

## Postassium hexafluoroplatinate (V) = Tetrafluoroplatinum(IV)

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Equation Result #1

 2K[PtF6] → F2 + 2KF + 2PtF4 Postassium hexafluoroplatinate (V) fluorine Tetrafluoroplatinum(IV) 2 1 2 2 Hệ số Nguyên - Phân tử khối (g/mol) Số mol Khối lượng (g)

## Further information about equation 2K[PtF6] → F2+ 2KF + 2PtF4

### What is reaction condition of K[PtF6] (Postassium hexafluoroplatinate (V)) ?

Temperature: 750°C

Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.

### Phenomenon after K[PtF6] (Postassium hexafluoroplatinate (V))

This equation does not have any specific information about phenomenon.

In this case, you just need to observe to see if product substance PtF4 (Tetrafluoroplatinum(IV)), appearing at the end of the reaction.

Or if any of the following reactant substances K[PtF6] (Postassium hexafluoroplatinate (V)), disappearing

## Further questions related to chemical reactions 2K[PtF6] → F2+ 2KF + 2PtF4

### Questions related to product PtF4 (Tetrafluoroplatinum(IV))

#### Extra information about substances that equation use

produce F2 (flo) and PtF4 (Tetrafloroplatin(IV)) ,temperature condition 750

#### Reaction that produces substance K[PtF6] (Kali hexafloroplatinat(V)) (Postassium hexafluoroplatinate (V))

No reaction found