# BeO NH4HF2 = H2O (NH4)2[BeF4] | Chemical Equation Balancer

## Ammonium hydrogenfluoride[F2H5N]; Ammonium hydrogen fluoride; Flammon; Ammonium difluoride; Ammonium bifluoride; Acid ammonium fluoride =

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Equation Result #1

 BeO + 2NH4HF2 → H2O + (NH4)2[BeF4] beryllium oxide Ammonium hydrogenfluoride[F2H5N]; Ammonium hydrogen fluoride; Flammon; Ammonium difluoride; Ammonium bifluoride; Acid ammonium fluoride water 1 2 1 1 Hệ số Nguyên - Phân tử khối (g/mol) Số mol Khối lượng (g)

## Further information about equation BeO + 2NH4HF2 → H2O + (NH4)2[BeF4]

### What is reaction condition of BeO (beryllium oxide) reacts with NH4HF2 (Ammonium hydrogenfluoride[F2H5N]; Ammonium hydrogen fluoride; Flammon; Ammonium difluoride; Ammonium bifluoride; Acid ammonium fluoride) ?

Temperature: 100 - 200°C

Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.

### Phenomenon after BeO (beryllium oxide) reacts with NH4HF2 (Ammonium hydrogenfluoride[F2H5N]; Ammonium hydrogen fluoride; Flammon; Ammonium difluoride; Ammonium bifluoride; Acid ammonium fluoride)

This equation does not have any specific information about phenomenon.

In this case, you just need to observe to see if product substance (NH4)2[BeF4], appearing at the end of the reaction.

Or if any of the following reactant substances NH4HF2 (Ammonium hydrogenfluoride[F2H5N]; Ammonium hydrogen fluoride; Flammon; Ammonium difluoride; Ammonium bifluoride; Acid ammonium fluoride), disappearing

## Further questions related to chemical reactions BeO + 2NH4HF2 → H2O + (NH4)2[BeF4]

### Questions related to product (NH4)2[BeF4] ()

#### Extra information about substances that equation use

Reaction of BeO (Berili oxit) react with NH4HF2 (Amoni Biflorua) produce H2O (nước) ,temperature condition 100 - 200