# tat-ca = I2 | Chemical Equation Balancer

## = iodine

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Equation Result #1

 H2SO4 + 8HI → 4H2O + H2S + 4I2 sulfuric acid hydroiodic acid water hydrogen sulfide iodine (dd đậm đặc) (lỏng) (khí) (rắn) (không màu) (không màu) (đen tím) 1 8 4 1 4 Hệ số Nguyên - Phân tử khối (g/mol) Số mol Khối lượng (g)

## Further information about equation H2SO4+ 8HI → 4H2O + H2S + 4I2

### What is reaction condition of H2SO4 (sulfuric acid) reacts with HI (hydroiodic acid) ?

Temperature: temperature

Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.

### Phenomenon after H2SO4 (sulfuric acid) reacts with HI (hydroiodic acid)

This equation does not have any specific information about phenomenon.

In this case, you just need to observe to see if product substance I2 (iodine), appearing at the end of the reaction.

Or if any of the following reactant substances HI (hydroiodic acid), disappearing

## Further questions related to chemical reactions H2SO4+ 8HI → 4H2O + H2S + 4I2

### Questions related to product I2 (iodine)

Equation Result #2

 H2O2 + H2SO4 + KI → H2O + I2 + K2SO4 hydrogen peroxide sulfuric acid potassium iodide water iodine potassium sulfate (lỏng) (dung dịch) (rắn) (lỏng) (rắn) (rắn) (không màu) (không màu) (trắng) (không màu) (đen tím) (trắng) 1 1 1 1 1 1 Hệ số Nguyên - Phân tử khối (g/mol) Số mol Khối lượng (g)

## Further information about equation H2O2+ H2SO4+ KI → H2O + I2+ K2SO4

### What is reaction condition of H2O2 (hydrogen peroxide) reacts with H2SO4 (sulfuric acid) reacts with KI (potassium iodide) ?

No information found for this chemical equation

Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.

### How reactions can happened and produce H2O (water) and I2 (iodine) and K2SO4 (potassium sulfate) ?

KI reacts with H2O2 in acid environment

### Phenomenon after H2O2 (hydrogen peroxide) reacts with H2SO4 (sulfuric acid) reacts with KI (potassium iodide)

This equation does not have any specific information about phenomenon.

In this case, you just need to observe to see if product substance K2SO4 (potassium sulfate), appearing at the end of the reaction.

Or if any of the following reactant substances KI (potassium iodide), disappearing

## Further questions related to chemical reactions H2O2+ H2SO4+ KI → H2O + I2+ K2SO4

### Questions related to product K2SO4 (potassium sulfate)

Equation Result #3

 K2Cr2O7 + 6KI + 14KHSO4 → 7H2O + 3I2 + 11K2SO4 + Cr2(SO4)3 Potassium dichromate; Potassium bichromate; Dichromic acid dipotassium salt potassium iodide water iodine potassium sulfate Chromic sulfate; Chromium(III) sulfate (rắn) (rắn) (rắn) (lỏng) (rắn) (rắn) (rắn) (trắng) (không màu) (đen tím) (trắng) 1 6 14 7 3 11 1 Hệ số Nguyên - Phân tử khối (g/mol) Số mol Khối lượng (g)

## Further information about equation K2Cr2O7+ 6KI + 14KHSO4 → 7H2O + 3I2+ 11K2SO4+ Cr2(SO4)3

### What is reaction condition of K2Cr2O7 (Potassium dichromate; Potassium bichromate; Dichromic acid dipotassium salt) reacts with KI (potassium iodide) reacts with KHSO4 () ?

No information found for this chemical equation

Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.

### Phenomenon after K2Cr2O7 (Potassium dichromate; Potassium bichromate; Dichromic acid dipotassium salt) reacts with KI (potassium iodide) reacts with KHSO4 ()

Click to see equation's phenomenon

## Further questions related to chemical reactions K2Cr2O7+ 6KI + 14KHSO4 → 7H2O + 3I2+ 11K2SO4+ Cr2(SO4)3

### Questions related to product Cr2(SO4)3 (Chromic sulfate; Chromium(III) sulfate)

Equation Result #4

 2H2SO4 + 2NaI + 2NaNO2 → 2H2O + I2 + 2Na2SO4 + 2NO sulfuric acid sodium iodide sodium nitrite water iodine sodium sulfate nitrogen monoxide (dung dịch) (rắn) (rắn) (lỏng) (rắn) (rắn) (khí) (không màu) (trắng) (không màu) (đen tím) (trắng) (không màu) 2 2 2 2 1 2 2 Hệ số Nguyên - Phân tử khối (g/mol) Số mol Khối lượng (g)

## Further information about equation 2H2SO4+ 2NaI + 2NaNO2 → 2H2O + I2+ 2Na2SO4+ 2NO

### What is reaction condition of H2SO4 (sulfuric acid) reacts with NaI (sodium iodide) reacts with NaNO2 (sodium nitrite) ?

No information found for this chemical equation

Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.

### Phenomenon after H2SO4 (sulfuric acid) reacts with NaI (sodium iodide) reacts with NaNO2 (sodium nitrite)

Click to see equation's phenomenon

### What are other important informations you should know about reaction

NaI solution is acidized with dilute H2SO4 and NaNO2

## Further questions related to chemical reactions 2H2SO4+ 2NaI + 2NaNO2 → 2H2O + I2+ 2Na2SO4+ 2NO

### Questions related to product NO (nitrogen monoxide)

Equation Result #5

 2CuI → 2Cu + I2 Cuprous iodide(CuI); Copper(I) iodide(CuI); Marshite; Copper(I) iodide; Iodocopper(I) copper iodine 2 2 1 Hệ số Nguyên - Phân tử khối (g/mol) Số mol Khối lượng (g)

## Further information about equation 2CuI → 2Cu + I2

### What is reaction condition of CuI (Cuprous iodide(CuI); Copper(I) iodide(CuI); Marshite; Copper(I) iodide; Iodocopper(I)) ?

Other Condition: light

Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.

### Phenomenon after CuI (Cuprous iodide(CuI); Copper(I) iodide(CuI); Marshite; Copper(I) iodide; Iodocopper(I))

This equation does not have any specific information about phenomenon.

In this case, you just need to observe to see if product substance I2 (iodine), appearing at the end of the reaction.

Or if any of the following reactant substances CuI (Cuprous iodide(CuI); Copper(I) iodide(CuI); Marshite; Copper(I) iodide; Iodocopper(I)), disappearing