# K = tat-ca | Chemical Equation Balancer

## potassium =

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Equation Result #1

 K + O2 → KO2 potassium oxygen Potassium superoxide; Potassium hyperoxide; Potassium dioxide 1 1 1 Hệ số Nguyên - Phân tử khối (g/mol) Số mol Khối lượng (g)

## Further information about equation K + O2 → KO2

### What is reaction condition of K (potassium) reacts with O2 (oxygen) ?

Temperature: temperature

Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.

### Phenomenon after K (potassium) reacts with O2 (oxygen)

This equation does not have any specific information about phenomenon.

In this case, you just need to observe to see if product substance KO2 (Potassium superoxide; Potassium hyperoxide; Potassium dioxide), appearing at the end of the reaction.

Or if any of the following reactant substances O2 (oxygen), disappearing

## Further questions related to chemical reactions K + O2 → KO2

### Questions related to product KO2 (Potassium superoxide; Potassium hyperoxide; Potassium dioxide)

Equation Result #2

 Br2 + 2K → 2KBr bromine potassium potassium bromide 1 2 2 Hệ số Nguyên - Phân tử khối (g/mol) Số mol Khối lượng (g)

## Further information about equation Br2+ 2K → 2KBr

### What is reaction condition of Br2 (bromine) reacts with K (potassium) ?

Temperature: room temperature

Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.

### Phenomenon after Br2 (bromine) reacts with K (potassium)

This equation does not have any specific information about phenomenon.

In this case, you just need to observe to see if product substance KBr (potassium bromide), appearing at the end of the reaction.

Or if any of the following reactant substances K (potassium), disappearing

## Further questions related to chemical reactions Br2+ 2K → 2KBr

### Questions related to product KBr (potassium bromide)

Equation Result #3

 2K + 2NH3 → H2 + 2KNH2 potassium ammonia hydrogen Potassium amide; Aminopotassium (khí) 2 2 1 2 Hệ số Nguyên - Phân tử khối (g/mol) Số mol Khối lượng (g)

## Further information about equation 2K + 2NH3 → H2+ 2KNH2

### What is reaction condition of K (potassium) reacts with NH3 (ammonia) ?

Temperature: 65 - 105°C

Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.

### Phenomenon after K (potassium) reacts with NH3 (ammonia)

This equation does not have any specific information about phenomenon.

In this case, you just need to observe to see if product substance KNH2 (Potassium amide; Aminopotassium), appearing at the end of the reaction.

Or if any of the following reactant substances NH3 (ammonia), disappearing

## Further questions related to chemical reactions 2K + 2NH3 → H2+ 2KNH2

### Questions related to product KNH2 (Potassium amide; Aminopotassium)

Equation Result #4

 4K + SiCl4 → 4KCl + Si potassium silicon tetrachloride potassium chloride silicon (vô định hình) 4 1 4 1 Hệ số Nguyên - Phân tử khối (g/mol) Số mol Khối lượng (g)

## Further information about equation 4K + SiCl4 → 4KCl + Si

### What is reaction condition of K (potassium) reacts with SiCl4 (silicon tetrachloride) ?

Temperature: 600 - 700°C

Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.

### Phenomenon after K (potassium) reacts with SiCl4 (silicon tetrachloride)

This equation does not have any specific information about phenomenon.

In this case, you just need to observe to see if product substance Si (silicon), appearing at the end of the reaction.

Or if any of the following reactant substances SiCl4 (silicon tetrachloride), disappearing

## Further questions related to chemical reactions 4K + SiCl4 → 4KCl + Si

### Questions related to product Si (silicon)

Equation Result #5

 2H2S + 2K → H2 + 2KHS hydrogen sulfide potassium hydrogen Potassium hydrogensulfide; Potassium hydrosulfide (bão hòa) (khí) (kt) 2 2 1 2 Hệ số Nguyên - Phân tử khối (g/mol) Số mol Khối lượng (g)

## Further information about equation 2H2S + 2K → H2+ 2KHS

### What is reaction condition of H2S (hydrogen sulfide) reacts with K (potassium) ?

Catalyst: on Benzene

Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.

### Phenomenon after H2S (hydrogen sulfide) reacts with K (potassium)

This equation does not have any specific information about phenomenon.

In this case, you just need to observe to see if product substance KHS (Potassium hydrogensulfide; Potassium hydrosulfide), appearing at the end of the reaction.

Or if any of the following reactant substances K (potassium), disappearing