# K = tat-ca | Chemical Equation Balancer

## potassium =

Equation Result #1

 2H2O + 2K + CuSO4 → Cu(OH)2 + H2 + K2SO4 water potassium copper(ii) sulfate copper(ii) hydroxide hydrogen potassium sulfate (lỏng) (rắn) (lỏng) (rắn) (khí) (lỏng) (không màu) (trắng) (xanh) (xanh) (không màu) (không màu) 2 2 1 1 1 1 Hệ số Nguyên - Phân tử khối (g/mol) Số mol Khối lượng (g)

## Further information about equation 2H2O + 2K + CuSO4 → Cu(OH)2+ H2+ K2SO4

### What is reaction condition of H2O (water) reacts with K (potassium) reacts with CuSO4 (copper(ii) sulfate) ?

No information found for this chemical equation

Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.

### Phenomenon after H2O (water) reacts with K (potassium) reacts with CuSO4 (copper(ii) sulfate)

This equation does not have any specific information about phenomenon.

In this case, you just need to observe to see if product substance K2SO4 (potassium sulfate), appearing at the end of the reaction.

Or if any of the following reactant substances CuSO4 (copper(ii) sulfate), disappearing

## Further questions related to chemical reactions 2H2O + 2K + CuSO4 → Cu(OH)2+ H2+ K2SO4

### Questions related to product K2SO4 (potassium sulfate)

Equation Result #2

 2H2O + 2K → H2 + 2KOH water potassium hydrogen potassium hydroxide (lỏng) (rắn) (khí) (dung dịch) (không màu) (trắng bạc) (không màu) 2 2 1 2 Hệ số Nguyên - Phân tử khối (g/mol) Số mol Khối lượng (g)

## Further information about equation 2H2O + 2K → H2+ 2KOH

### What is reaction condition of H2O (water) reacts with K (potassium) ?

No information found for this chemical equation

Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.

### How reactions can happened and produce H2 (hydrogen) and KOH (potassium hydroxide) ?

Potassium reacts with water

### Phenomenon after H2O (water) reacts with K (potassium)

Click to see equation's phenomenon

## Further questions related to chemical reactions 2H2O + 2K → H2+ 2KOH

### Questions related to product KOH (potassium hydroxide)

Equation Result #3

 Cl2 + 2K → 2KCl chlorine potassium potassium chloride (khí) (rắn) (rắn) (vàng lục) (trắng bạc) (trắng) 1 2 2 Hệ số Nguyên - Phân tử khối (g/mol) Số mol Khối lượng (g)

## Further information about equation Cl2+ 2K → 2KCl

### What is reaction condition of Cl2 (chlorine) reacts with K (potassium) ?

Temperature: room temperature

Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.

### How reactions can happened and produce KCl (potassium chloride) ?

Chlorine reacts with potassium

### Phenomenon after Cl2 (chlorine) reacts with K (potassium)

This equation does not have any specific information about phenomenon.

In this case, you just need to observe to see if product substance KCl (potassium chloride), appearing at the end of the reaction.

Or if any of the following reactant substances K (potassium), disappearing

## Further questions related to chemical reactions Cl2+ 2K → 2KCl

### Questions related to product KCl (potassium chloride)

Equation Result #4

 I2 + 2K → 2KI iodine potassium potassium iodide (rắn) (rắn) (rắn) (đen tím) (trắng bạc) (trắng) 1 2 2 Hệ số Nguyên - Phân tử khối (g/mol) Số mol Khối lượng (g)

## Further information about equation I2+ 2K → 2KI

### What is reaction condition of I2 (iodine) reacts with K (potassium) ?

Temperature: temperature

Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.

### How reactions can happened and produce KI (potassium iodide) ?

Iodine reacts with potassium

### Phenomenon after I2 (iodine) reacts with K (potassium)

This equation does not have any specific information about phenomenon.

In this case, you just need to observe to see if product substance KI (potassium iodide), appearing at the end of the reaction.

Or if any of the following reactant substances K (potassium), disappearing

## Further questions related to chemical reactions I2+ 2K → 2KI

### Questions related to product KI (potassium iodide)

Equation Result #5

 2K + S → K2S potassium sulfur potassium sulfide (rắn) (rắn) (rắn) (trắng bạc) (vàng chanh) 2 1 1 Hệ số Nguyên - Phân tử khối (g/mol) Số mol Khối lượng (g)

## Further information about equation 2K + S → K2S

### What is reaction condition of K (potassium) reacts with S (sulfur) ?

Temperature: 100 - 200°C

Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.

K reacts with S

### Phenomenon after K (potassium) reacts with S (sulfur)

This equation does not have any specific information about phenomenon.

In this case, you just need to observe to see if product substance K2S (potassium sulfide), appearing at the end of the reaction.

Or if any of the following reactant substances S (sulfur), disappearing

## Further questions related to chemical reactions 2K + S → K2S

### Questions related to product K2S (potassium sulfide)

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