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Fe3O4 = tat-ca | Chemical Equation Balancer

iron(ii,iii) oxide =

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Equation Result #1


8HI + Fe3O44H2O + I2 + 3FeI2
hydroiodic acid iron(ii,iii) oxide water iodine Iron(II) iodide; Ferrous iodide; Iron(II) diiodide
8 1 4 1 3 Hệ số
Nguyên - Phân tử khối (g/mol)
Số mol
Khối lượng (g)

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Condition

No information found for this chemical equation

Phenomenon

This equation does not have any specific information about phenomenon.

In this case, you just need to observe to see if product substance FeI2 (Iron(II) iodide; Ferrous iodide; Iron(II) diiodide), appearing at the end of the reaction.

Or if any of the following reactant substances Fe3O4 (iron(ii,iii) oxide), disappearing

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Equation Result #2


8H3PO4 + 3Fe3O412H2O + Fe3(PO4)2 + 6FePO4
Sonac; Phosphoric acid; Orthophosphoric acid; Phosphoric acid hydrogen iron(ii,iii) oxide water Iron(II) Phosphate Phosphoric acid iron(III) salt; Iron(III) phosphate; Iron(III) orthophosphate
8 3 12 1 6 Hệ số
Nguyên - Phân tử khối (g/mol)
Số mol
Khối lượng (g)

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Condition

No information found for this chemical equation

Phenomenon

This equation does not have any specific information about phenomenon.

In this case, you just need to observe to see if product substance FePO4 (Phosphoric acid iron(III) salt; Iron(III) phosphate; Iron(III) orthophosphate), appearing at the end of the reaction.

Or if any of the following reactant substances Fe3O4 (iron(ii,iii) oxide), disappearing

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Equation Result #3


(46x-18y)HNO3 + (5x-2Fe3O4(23x-9y)H2O + (15x-6y)Fe(NO3)3 + NxOy
nitric acid iron(ii,iii) oxide water iron(iii) nitrate Nitrogen oxide
(46x-18y) (5x-2 (23x-9y) (15x-6y) 1 Hệ số
Nguyên - Phân tử khối (g/mol)
Số mol
Khối lượng (g)

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Condition

No information found for this chemical equation

Phenomenon

This equation does not have any specific information about phenomenon.

In this case, you just need to observe to see if product substance NxOy (Nitrogen oxide), appearing at the end of the reaction.

Or if any of the following reactant substances Fe3O4 (iron(ii,iii) oxide), disappearing

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We have been working with Google to develop an advanced search with results filted with chemistry topic only

Click here to find more information about this equation

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