Equation Result #1
2KI | + | SO3 | → | I2 | + | K2SO3 | |
potassium iodide | iodine | ||||||
(rắn) | (lỏng) | (rắn) | (rắn) | ||||
(trắng) | (không màu) | (đen tím) | |||||
2 | 1 | 1 | 1 | Hệ số | |||
Nguyên - Phân tử khối (g/mol) | |||||||
Số mol | |||||||
Khối lượng (g) |
Temperature: temperature
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
KI reacts with K2SO3
We no further information about this chemical reactions.
Equation Result #2
SO2 | + | 2KOH.2H2O | → | 5H2O | + | K2SO3 | |
sulfur dioxide | Potassium hydroxide dihydrate | water | |||||
(khí) | (lỏng) | (lỏng) | (lỏng) | ||||
(không màu) | (không màu) | (không màu) | (không màu) | ||||
1 | 2 | 5 | 1 | Hệ số | |||
Nguyên - Phân tử khối (g/mol) | |||||||
Số mol | |||||||
Khối lượng (g) |
No information found for this chemical equation
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance K2SO3, appearing at the end of the reaction.
Or if any of the following reactant substances KOH.2H2O (Potassium hydroxide dihydrate), disappearing
We no further information about this chemical reactions.
Equation Result #3
6KOH | + | 3S | → | 3H2O | + | 2K2S | + | K2SO3 | |
potassium hydroxide | sulfur | water | potassium sulfide | ||||||
(dung dịch) | (rắn) | (khí) | (rắn) | (rắn) | |||||
(không màu) | (vàng) | (không màu) | (không màu) | (không màu) | |||||
6 | 3 | 3 | 2 | 1 | Hệ số | ||||
Nguyên - Phân tử khối (g/mol) | |||||||||
Số mol | |||||||||
Khối lượng (g) |
No information found for this chemical equation
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance K2SO3, appearing at the end of the reaction.
Or if any of the following reactant substances S (sulfur), disappearing
We no further information about this chemical reactions.
Equation Result #4
2KOH | + | SO2 | → | H2O | + | K2SO3 | |
potassium hydroxide | sulfur dioxide | water | |||||
(lỏng) | (khí) | (lỏng) | (rắn) | ||||
(không màu) | (không màu) | (không màu) | (trắng) | ||||
2 | 1 | 1 | 1 | Hệ số | |||
Nguyên - Phân tử khối (g/mol) | |||||||
Số mol | |||||||
Khối lượng (g) |
No information found for this chemical equation
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
This equation does not have any specific information about phenomenon.
In this case, you just need to observe to see if product substance K2SO3, appearing at the end of the reaction.
Or if any of the following reactant substances SO2 (sulfur dioxide), disappearing
We no further information about this chemical reactions.
Equation Result #5
No information found for this chemical equation
Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations.
We no further information about this chemical reactions.
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