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? = CH3CN | Chemical Equation Balancer

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Equation Result #1


CH3Br + KCNKBr + CH3CN
potassium cyanide potassium bromide
(khí) (lỏng) (lỏng) (lỏng)
(Không màu) (Không màu) (Không màu) (Không màu)
1 1 1 1 Hệ số
Nguyên - Phân tử khối (g/mol)
Số mol
Khối lượng (g)

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Condition

No information found for this chemical equation

Phenomenon

This equation does not have any specific information about phenomenon.

In this case, you just need to observe to see if product substance CH3CN, appearing at the end of the reaction.

Or if any of the following reactant substances KCN (potassium cyanide), disappearing

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Extra information about substances that equation use

Reaction of CH3Br (Metyl Bromua) react with KCN (Kali Xyanua) produce KBr (kali bromua)

Reaction that produces substance CH3Br (Metyl Bromua) ()

CH3OH + HBr => H2O + CH3Br Br2 + CH4 => CH3Br + HBr

Reaction that produces substance KCN (Kali Xyanua) (potassium cyanide)

KOH + NH4CN => NH4OH + KCN 4C + K2CO3 + N2 => 3CO + 2KCN H2O + K3[Fe(CN)6] => KCN + K2[Fe(H2O)(CN)5]

Reaction that produces substance KBr (kali bromua) (potassium bromide)

KI + CH3CH(Br)CH2(Br) => KBr + IBr + CH2=CHCH3 3Br2 + 3K2CO3 => 5KBr + 3CO2 + KBrO3 2KMnO4 + 16HBr => Br2 + 8H2O + 2KBr + 2MnBr2

Reaction that produces substance CH3CN (Metyl Xyanua) ()

CH3Br + KCN => KBr + CH3CN

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